12x/x^2+5x+6+7/x+3

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Solution for 12x/x^2+5x+6+7/x+3 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x+(12*x)/(x^2)+7/x+3+6 = 0

5*x^1+19*x^-1+9*x^0 = 0

(5*x^2+9*x^1+19*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2+9*x^1+19*x^0) = 0

x^1

5*x^2+9*x+19 = 0

5*x^2+9*x+19 = 0

DELTA = 9^2-(4*5*19)

DELTA = -299

DELTA < 0

x in { }

x belongs to the empty set

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